Answer:
Not possible
Step-by-step explanation:
supposing both the roots as α and β and a,b and c are all positive real numbers.
Then α+β= -b/a which will be negative
⇒ α+β<0
and αβ= c/a , which will positive
⇒αβ>0
also, -b/a>0 and c/a<0
⇒b/a<0 and c/a<0 which is not possible because all a, b and c are positive real numbers.
hence, it is not possible that the quadratic equation ax²+bx+c=0 has a positive real solution if a,b and c are all positive real numbers
