Answer: 1.29 x 10^24 atoms of Nitrogen is present
Explanation:
molar mass of NO = 14 +16 = 30g/mol
number of moles of NO = 4.58mol
number of moles of Nitrogen in NO is = (14/30)x4.58= 2.1373 moles
To get the number of atoms of Nitrogen we use Avogadro's number
Number of atoms of Nitrogen= mole fraction of Nitrogen x Avogadro's constant = 2.1373 x 6.02 x 10^23 = 1.29 x 10^24 atoms
