Answer:
[tex]3 Mg(s) + N_2(g) = Mg_3N_2(s)[/tex]
Explanation:
The valance of magnesium atom is [tex]+2[/tex]
While the valence of nitrogen atom is [tex]- 3[/tex]
Let us first write the first half-reactions
[tex]Mg ---> Mg^{2+} + 2e^{-}[/tex]
The second half reaction is
[tex]2N + 6e^- -----> N_2[/tex]
Adding the above two reactions and writing the final reaction, we get -
[tex]Mg + N2 = Mg_3N_2[/tex]
The balance equation is
[tex]3 Mg(s) + N_2(g) = Mg_3N_2(s)[/tex]
