identify all the hyperbolas which open horizontally. (x+2)^2/3^2 - (2y-10)^2/8^2 =1 (x-1)^2/6^2 - (2y+6)^2/52 =1 (2y-6)^2/3^2 - (x+6)^2/2^2 = 1 (y+4)^2/8^2 - (2x-3)^2/30^2= 1. (2y-10)^2/10^2 -(x+3)^2/12^2 =1 (y+1)^2/4^2 - (2x-8)^2/15^2 = 1