an electrochemical cell is based on two half- reactions: oxidation: Ox: Pb(s)→Pb2+(aq, 0.16 M )+2e−
Red: MnO−4(aq, 1.70 M )+4H+(aq, 1.9 M )+3e−→ MnO2(s)+2H2O(l)
Part A Compute the cell potential at 25 ∘C.