screamolover5113 screamolover5113

22-02-2024
Engineering

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Given the following:
(KE)avg 3RT/2 = (average kinetic energy per mole for a monatomic ideal gas)
∆E = q + w
w = -PAV (Note the sign!)
q = nC∆T (where C is the molar heat capacity.)
ΔΗ = ΔΕ + ∆(PV)
For the case of a monatomic ideal gas, select correct equivalent expressions for the quantities listed.
∆E
a. 5/2 nR∆T
b. nCv∆T
c. 3/2 R
d. Cv+R

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