allieballey0727 allieballey0727

21-05-2018
Mathematics

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please help with this! asap

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Respuesta :

14-09-2018

[tex]6\dfrac{2}{3}-1\dfrac{1}{4}=6\dfrac{2\cdot4}{3\cdot4}-1\dfrac{1\cdot3}{4\cdot3}=6\dfrac{8}{12}-1\dfrac{3}{12}=(6-1)+\dfrac{8-3}{12}=\boxed{5\dfrac{5}{12}}[/tex]

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