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25-07-2018
Mathematics

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if [tex] (x+y)^{2} [/tex]=36 and xy= -7, findthe value of [tex] x^{2}+y^{2} [/tex]

Respuesta :

25-07-2018

[tex](x + y)^2 = 36[/tex]

[tex]x^2 + 2xy + y^2 = 36[/tex]

[tex]x^2+ y^2 = 36 - 2xy = 36- 2(-7)= 36+14=50[/tex]

Answer: 50

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