isabelgalvarado2261 isabelgalvarado2261
  • 25-07-2018
  • Chemistry
contestada

What is the molality of a solution prepared by dissolving 82.2 g of ethylene glycol, hoch2ch2oh, in 1.50 l of water? assume the density of water is 1.00 g/ml?

Respuesta :

isyllus
isyllus isyllus
  • 30-07-2018

Answer:-

0.883 m

Explanation:-

Molality= Moles per Kg of solvent.

Molar mass of ethylene glycol= 62.07 g/ mol.

Number of moles of ethylene glycol= 82.2g / (62.07 g/mol)

= 1.324 moles

Density of water = 1 g/ml = (1/1000kg)/ (1/1000litre)

= 1 Kg / litre

Mass of 1.5 litre of water = 1.5 litre x 1 kg / litre

= 1.5 kg

Molality of ethylene glycol = 1.324 moles/1.5 kg

= 0.883 m

Answer Link

Otras preguntas

What is 7x-4(3x-2)=18
solve each linear equation solve for x6x - 10 = -8 + 3x​
How do catalysts affect a chemical reaction? lower activation energy provide activation energy increase activation energy lose activation energy
let help and step by by explanation ​
0.736euros= 1us dollar
help me please.......​
5 An arithmetic progression has a second term of -14 and a sum to 21 terms of 84. Find the first term and the 21st term of this progression.​
In Ohm's Law, it states that the current in the circuit is directionally proportional to the voltage in that circuit. Explain what you understand stand by this.
What's 3.8888888888... as a fraction? show work please help
Please answer this. .