angelsesmas112pdwev9 angelsesmas112pdwev9
  • 23-08-2018
  • Mathematics
contestada

5x-3x+7=3x-1
[tex]4r + \frac{2}{4} r + 14 = 5r - \frac{3}{4} r + 1 - 3[/tex]

Respuesta :

mkryukova19 mkryukova19
  • 23-08-2018

1). 5x-3x+7 = 3x-1

2x + 7 = 3x - 1

3x-2x=7+1

x=8

2)

[tex] 4r + \frac{2}{4} r + 14 = 5r - \frac{3}{4} r + 1 - 3\\ \\5r-4r-\frac{3}{4} r - \frac{2}{4} r = 14-1+3\\ \\r-\frac{5}{4}r =16\\ \\\frac{4}{4}r-\frac{5}{4}r =16\\ \\-\frac{1}{4}r=16\\ \\ r=-64 [/tex]

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