The choices you provided do not match the question!!!
Tickets ($25): x
T-shirts ($12): y
25x + 12y + 4 ≤ 130
Since she bought 3 tickets: 25(3) + 12y + 4 ≤ 130
75 + 12y + 4 ≤ 130
79 + 12y ≤ 130
12y ≤ 51
y ≤ [tex]\frac{51}{12}[/tex]
y ≤ 4[tex]\frac{1}{4}[/tex]
Since you cant buy [tex]\frac{1}{4}[/tex] of a T-shirt, the maximum number of T-shirts she can purchase is 4.
