gracenicole1124 gracenicole1124
  • 23-09-2018
  • Mathematics
contestada

Write the equation of a line that is perpendicular to y=0.3x+6 and that passes through the point (3,-8)

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tramserran
tramserran tramserran
  • 23-09-2018

First, find the perpendicular slope

y = 0.3x + 6   ⇒ m = 0.3  = [tex]\frac{3}{10}[/tex]

perpendicular slope =  [tex]-\frac{10}{3}[/tex]

Next, input the point (x₁, y₁) and slope (m) into the Point-Slope formula

  y - y₁ = m(x - x₁)

y - (-8) = [tex]-\frac{10}{3}[/tex](x - 3)

 y + 8 = [tex]-\frac{10}{3}x[/tex] + 10

      y = [tex]-\frac{10}{3}[/tex] + 2


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