mocks2681 mocks2681
  • 24-11-2018
  • Mathematics
contestada

Find an equation of the tangent line to the curve at the given point. y = 3x3 - x2 + 2, (1, 4)

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jimrgrant1 jimrgrant1
  • 24-11-2018

y = 7x - 3

Note the gradient of the tangent is the derivative of y at x = 1

Differentiate using the power rule

[tex]\frac{d}{dx}[/tex](a[tex]x^{n}[/tex]) = na[tex]x^{n-1}[/tex]

y = 3x³ - x² + 2

[tex]\frac{dy}{dx}[/tex] = 9x² - 2x

x = 1 : [tex]\frac{dy}{dx}[/tex] = 9 - 2 = 7 ← gradient of tangent

equation in point- slope form, using m = 7 and (a, b) = (1, 4)

y - 4 = 7(x - 1) ← point-slope form

y - 4 = 7x - 7

y = 7x - 3 ← in slope-intercept form



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