Answer:
x ≤ -11, Yes. The solution set include -11.
Step-by-step explanation:
[tex]x+4\leq\dfrac{1}{2}(x-3)\qquad\text{multiply both sides by 2}\\\\2x+8\leq1(x-3)\\\\2x+8\leq x-3\qquad\text{subtract 8 from both sides}\\\\2x\leq x-11\qquad\text{subtract x from both sides}\\\\\boxed{x\leq-11}[/tex]
