Answer:
b. [tex]\frac{x+3}{x-1}[/tex]
Step-by-step explanation:
Given expression is:
[tex]\frac{x^{2}-9 }{(x-1)(x-3)}[/tex]
Let us factorize the numerator using the formula:
[tex]a^{2} -b^{2} =(a+b)(a-b)[/tex]
[tex]\frac{(x+3)(x-3)}{(x-1)(x-3)}[/tex]
Since x ≠ 3, let us cancel the common factor x - 3 in the numerator and in the denominator.
So, [tex]\frac{x^{2}-9 }{(x-1)(x-3)} =\frac{x+3}{x-1}[/tex]
