cmoreno511 cmoreno511
  • 24-04-2019
  • Mathematics
contestada

Order of operations

The answer is 124 for prob . Please show steps . I keep getting 129

4^2×2^3- (14-16)÷2

Respuesta :

kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 04-05-2019

ANSWER

129

EXPLANATION

The given expression is:

[tex]4^2×2^3- (14-16)÷2[/tex]

Deal with the parenthesis first.

[tex]4^2×2^3- ( - 2)÷2[/tex]

[tex]4^2×2^3 + 2÷2[/tex]

Deal with exponents,

[tex]16×8+ 2÷2[/tex]

Divide now

[tex]16×8 + 1[/tex]

Multiply

[tex]128 + 1 [/tex]

You can now add to get

[tex]129[/tex]

The order of operations is PEDMAS

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