naydeen11j naydeen11j

25-05-2019
Mathematics

contestada

(-3)^3(2^6)/(-3)^5(2)^2=(2)^a/(-3)^b=c/d
What are the values of a,b,c,and d

Respuesta :

Аноним Аноним

29-05-2019

Answer:

See below in bold.

Step-by-step explanation:

(-3)^3(2^6)/(-3)^5(2)^2

= (-3)^(3-5)*(2^4)

= 2^4 / (-3)^2 so a = 4 and b = 2.

2^4 / (-3)^2

= 16/9 so c = 16 and d = 9.

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