mia370 mia370
  • 26-05-2019
  • Mathematics
contestada

What is the first four terms of 3n²

Respuesta :

r3t40
r3t40 r3t40
  • 26-05-2019

Suppose there is a function [tex]f(n)=3n^2, n\in\mathbb{N}[/tex].

We start counting by 1 from the first element in domain of natural numbers so: 1, 2, 3, 4.

We assemble the definition set [tex]A=\{1,2,3,4\}[/tex] than use the function f(n) to create transformation set:

[tex]f(A)=3\{1,2,3,4\}^2\Longrightarrow\{3,6,9,12\}^2 \\

\boxed{B=\{9,36,81,144\}}

[/tex]

So the first four terms are defined in transformation set B.

Hope this helps.

r3t40

Answer Link

Otras preguntas

Which statements describe polyatomic ions? Check all that apply. Polyatomic ions have many charges. Polyatomic ions have one overall charge. Polyatomic ions rep
The volume, V, of a rectangular prism is determined using the formula, where / is the length, w is the width, and his theheight of the prism. Carltren solves fo
The large connected urbane area from Boston to Washington, D.C. . Is often referred to as
If a textbook weighs 37.2 N on Venus, and the book has a mass of 4.4 kg, what is the strength of gravity on Venus?8.9 m/s28.9 m/sI don't have enough information
What contributed to the growth of Zionism in the late 1800s? Check all that apply.
Before you enter an intersection on a green light make sure
Find the nonpermissible replacement for binthis expression.b2/5b +5​
Which expression is equivalent to (x^4/3 x^2/3)^1/3?
-4(2x-1)>5-3x. HELP!
Will give Brainliest Summations with Algebraic Expressions Image Shown