Respuesta :

luana
[tex]\frac{2}{5}h-7=\frac{12}{5}h-2h+3\ \ \ |Multiply\ by\ 5\\\\ 2h-35=12h-10h+15\\\\ 2h-35=2h+15\ \ \ |Subtract\ 2h\\\\ -35 \neq 15\\\\There\ are\ no\ solutions.[/tex]
mariamikayla
[tex]\frac{2}{5h-7}=\frac{12}{5h-2h+3} \\\\ \frac{2}{5h-7}=\frac{12}{3h+3} \\\\ 2(3h+3)=12(5h-7) \\\\ 6h+6=60h-84 \\\\ 6h-60h=-84-6\\\\ -54h=-90 \\\\ \boxed{h=\frac{-90}{-54}=\frac{15}{9}=\frac{5}{3}}[/tex]