Answer:
Third option
Step-by-step explanation:
Given expression is:
[tex]\sqrt[3]{32x^8y^{10}}[/tex]
Making the exponents multiples of 3
[tex]=\sqrt[3]{8*4*x^6*x^2*y^{9}*y}\\=\sqrt[3]{2^3*4*x^6*x^2*y^{9}*y}\\Applying\ radical\\=2^{(3*\frac{1}{3})} *4^{\frac{1}{3} }*x^{(6*\frac{1}{3})}*x^{(2*\frac{1}{3})}*y^{(9*\frac{1}{3})}*y^{\frac{1}{3}}\\=2x^2y^3\sqrt[3]{4x^2y}[/tex]
Hence,
Option No 3 is correct ..
