If p(x) = x2 - 1 and (x)= 5(x-1), which expression is equivalent to (0-2)(x)?
5(x - 1) – x2 - 1
(5x - 1) – (x2 - 1)
(x2 - 1) – 5(x - 1)
(x2 - 1) – 5x-1