Answer:0.84164
Step-by-step explanation:
Given
[tex]\log \left ( 4\right )\cdot \log \left ( 25\right )[/tex]
we know
[tex]\log a^b=b\log a[/tex]
Applying this identity we get
[tex]\log \left ( 2\right )^2\cdot \log \left ( 5\right )^2[/tex]
[tex]=2\log \left ( 2\right )\times 2\log \left ( 5\right )[/tex]
[tex]=4\times \log \left ( 2\right )\cdot \left ( 5\right )[/tex]
[tex]=4\times 0.301029\times 0.698970[/tex]
[tex]=0.84164[/tex]
