Answer:
6.32 units
Explanation:
[tex]V_1=6.0 \hat {i} -7.0\hat{j}\\ V_2=\hat {i} +\hat{j}\\ V_3=-1.0 \hat {i} +4.0\hat{j}[/tex]
Adding the vectors
[tex]V_1+V_2+V_3=(6+1-1)\hat {i}+(-7+1+4)\hat {j}\\\Rightarrow V=6\hat {i}-2\hat {j}[/tex]
[tex]|V|=\sqrt{6^2+(-2)^2}\\\Rightarrow |V|=\sqrt{36+4}\\\Rightarrow |V|=\sqrt{40}\\\Rightarrow |V|=6.32\ units[/tex]
∴ Magnitude of the sum of the three vectors is 6.32 units
