Answer:
[tex]\huge{\boxed{x=\pm\dfrac{5}{4}}[/tex]
Step-by-step explanation:
[tex]12|x|-7=8\qquad\text{add 7 to both sides}\\\\12|x|-7+7=8+7\\\\12|x|=15\qquad\text{divide both sides by 12}\\\\\dfrac{12|x|}{12}=\dfrac{15}{12}\\\\|x|=\dfrac{15:3}{12:3}\\\\|x|=\dfrac{5}{4}\iff x=\pm\dfrac{5}{4}[/tex]
