Respuesta :

Willchemistry
Molar mass CuNO₃ = 125.55 g/mol

number of moles:

4.80 / 125.55 => 0.038 moles of CuNO₃

M = n / V

0.270 = 0.038 / V

V = 0.038 / 0.270

V = 0.1407 L

hope this helps!
sarajevo

Answer:

The volume of the solution is 0.0948 L

Explanation:

Molarity = moles/ L  

Moles = mass/ molar mass

Molarity = 0.27 M

Mass of Cu(NO₃)₂ = 4.8 g  

Molar mass of Cu(NO₃)₂= 187.56 g/mol

Moles = [tex]\frac{4.8 g}{187.56 g/mol }[/tex] = 0.0256

0.27 M = 0.0256 mol / L  

L = [tex]\frac{0.0256 mol}{0.27 M}[/tex] = 0.0948

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