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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Find the inverse of the given function.[tex]f(x)=-\frac{1}{2} \sqrt{x+3} ,x\geq -3[/tex]
f -1(x) = _ x^2 - _ , for x ≤ _

Respuesta :

amna04352

Answer:

(f^-1)(x) = 4x² - 3, x ≤ 0

Step-by-step explanation:

y = -½(sqrt(x+3))

Make x the subject

-2y = sqrt(x+3)

(-2y)² = x+3

x = 4y² - 3

(f^-1)(x) = 4x² - 3

Domain of f^-1 is the range of f

At x = -3, f(x) = 0

At x > -3, f(x) < 0

Range of f is ≤0

So domain on f^-1 is ≤ 0

Basaranj

Answer:

(f^-1)(x) = 4x² - 3, x ≤ 0

Step-by-step explanation:

On Plato put 4 in first box, 3 in second box, 0 in third box.

There you go.