Answer:
Step-by-step explanation:
Let the number to be added be x
[tex]4\frac{1}{8}+x=6\\\\x=6-4\frac{1}{8}\\\\x=6-\frac{33}{8}\\\\x=\frac{6*8}{1*8}-\frac{33}{8}\\\\x=\frac{48}{8}-\frac{33}{8}\\\\x=\frac{48-33}{8}\\\\x=\frac{15}{8}\\\\x=1\frac{7}{8}[/tex]
