Chicken45
Chicken45 Chicken45
  • 26-03-2020
  • Mathematics
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Calculus help because I am stuck on this question

Calculus help because I am stuck on this question class=

Respuesta :

LammettHash
LammettHash LammettHash
  • 26-03-2020

[tex]y=\left(\dfrac{x^2+2}{x^2-2}\right)^6[/tex]

Chain and power rule:

Let [tex]u=\frac{x^2+2}{x^2-2}[/tex]. By the chain rule,

[tex]y=u^6\implies y'=6u^5u'[/tex]

Quotient rule:

[tex]u=\dfrac{x^2+2}{x^2-2}\implies u'=\dfrac{(x^2-2)(x^2+2)'-(x^2+2)(x^2-2)'}{(x^2-2)^2}[/tex]

[tex]u'=\dfrac{2x(x^2-2)-2x(x^2+2)}{(x^2-2)^2}=-\dfrac{8x}{(x^2-2)^2}[/tex]

Putting everything together, we have

[tex]y'=6\left(\dfrac{x^2+2}{x^2-2}\right)^5\left(-\dfrac{8x}{(x^2-2)^2}\right)[/tex]

[tex]y'=-\dfrac{48x(x^2+2)^5}{(x^2-2)^7}[/tex]

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