allthingsrpossible allthingsrpossible
  • 22-04-2020
  • Mathematics
contestada

12x+7<-11 and 5x-8>= 40

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sqdancefan
sqdancefan sqdancefan
  • 22-04-2020

Answer:

  no solution

Step-by-step explanation:

First inequality:

  12x < -18 . . . . subtract 7

  x < -18/12 . . . divide by 12

  x < -1.5 . . . . . . write as decimal

__

Second inequality:

  5x -8 ≥ 40

  5x ≥ 48 . . . . . . add 8

  x ≥ 9.6 . . . . . . . divide by 5

__

There are no solutions to this pair of inequalities. No value of x can be both less than -1.5 and greater than 9.6.

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