Answer:
Total length of spring 0.647 m
Explanation:
We have given mass of the person m = 150 kg
Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]
Spring constant k = 10000 N/m
Nominal length of spring = 0.50
According to hook's law
[tex]mg=kx[/tex]
[tex]150\times 9.8=10000\times x[/tex]
x = 0.147 m
So total length of spring = 0.50+0.147 = 0.647 m
