killedpain killedpain
  • 22-08-2016
  • Mathematics
contestada

Solve for x:
e^ln5 = x
ln1 - lne = x
ln6 + ln(x) - ln(2) =3

Respuesta :

Panoyin
Panoyin Panoyin
  • 22-08-2016
[tex]e^{ln(5)} = x[/tex]
[tex]5 = x[/tex]

[tex]ln(1) - ln(e) = x[/tex]
[tex]0 + 1 = x[/tex]
[tex]1 = x[/tex]

[tex]ln(6) + ln(x) - ln(2) = 3[/tex]
[tex]ln(6) - ln(2) + ln(x) = 3[/tex]
[tex]\frac{ln(6)}{ln(2)} + ln(x) = 3[/tex]
[tex]\frac{ln(3) + ln(2)}{ln(2)} + ln(x) = 3[/tex]
[tex]\frac{ln(3)}{ln(2)} + 1 + ln(x) = 3[/tex]
[tex]\frac{ln(3)}{ln(2)} + ln(x) = 2[/tex]
[tex]\frac{ln(3x)}{ln(2)} = 2[/tex]
[tex]\frac{3x}{2} = e^{2}[/tex]
[tex]\frac{3x}{2} \approx 7.39[/tex]
[tex]3x = 14.78[/tex]
[tex]x \approx 4.926[/tex]
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