Answer:
[tex]x=\{3+\sqrt 2,\:\:3-\sqrt 2\}[/tex]
Step-by-step explanation:
[tex]6x-x^2-7=0\\x^2-6x +7=0\\x^2-2.3.x +3^2=3^2-7\\(x-3)^2=9-7\\\huge\boxed{(x-3)^2=2}...(square\: completed)\\x-3=\pm\sqrt{2} \\x=3+\pm\sqrt{2}\\\therefore x =3+\sqrt{2}\: or \: x =3-\sqrt{2}\\\therefore x =\{3+\sqrt{2},\:\:3-\sqrt{2}\}\\[/tex]
