Answer:
8.75° south of west
26.3 mph
Step-by-step explanation:
Let's say that east is +x and north is +y.
The sailor's horizontal velocity is -26 mph. The vertical velocity is -4 mph. So the velocity vector is in the 3rd quadrant. The direction is:
θ = tan⁻¹(-4 / -26)
θ = 188.75°, or 8.75° south of west.
The magnitude of the speed is:
v = √((-4)² + (-26)²)
v = 26.3 mph
