A total charge Q is distributed uniformly over a large flat insulating surface of area A . If the electric field magnitude is equal to 1000 NC/ at a point located a perpendicular distance of 0.1 m away from the center of the sheet, then the electric field at a point a perpendicular distance 0.2 m from the center of the sheet is:_______

a. 1000N/C
b. 500N/C
c. Impossible to say since we are not given Q and A
d. 250 N/C

Question

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Respuesta :

andromache andromache · Answer 1 · 2020-06-28T05:39:15+02:00

Answer:

a. 1000N/C

Explanation:

Data mentioned in the question

Electrical field magnitude = 1000 NC

Perpendicular distance = 0.1 m

Perpendicular distance = 0.2 m

Based on the above information, the electric field is

As we know that

[tex]E = \frac{\sigma}{2\times E_o}[/tex]

where,

[tex]\sigma[/tex] = surface charge density

E = distance from nearby point to sheet i.e be independent

The distance at 0.1 and 0.2, the electric field would remain the same

So,

Based on the above explanation, the first option is correct