Answer:
Option (B)
Step-by-step explanation:
[tex]\begin{bmatrix}4 & 0\\ -1 & 2\\ -3 & -1\end{bmatrix}\times\begin{bmatrix}0 & 1 \\ -3 & 1\end{bmatrix}[/tex]
In the multiplication of two matrices we multiply the column of 1st matrix with the row of the 2nd matrix and add them.
= [tex]\begin{bmatrix}(4\times 0)+0(-3) &(4)1+0(1)\\ (-1)0+2(-3) &(-1)1+2(1)\\ (-3)0+(-1)(-3) &(-3)1+(-1)1 \end{bmatrix}[/tex]
= [tex]\begin{bmatrix}0 &4\\ -6 &1\\ 3 &-4 \end{bmatrix}[/tex]
Therefore, Option (B) will be the answer.
