theman9879 theman9879
  • 24-08-2020
  • Mathematics
contestada

[tex]-r+(3r^{2}+1)r=4[/tex]

Respuesta :

Emurus
Emurus Emurus
  • 24-08-2020

Answer:

[tex]r = \sqrt[3]{\frac{4}{3} }[/tex]

Step-by-step explanation:

[tex]-r + (3r^2 + 1)r = 4\\-r + 3r^3 + r = 4\\3r^3 = 4\\r^3 = \frac{4}{3} \\\\r = \sqrt[3]{\frac{4}{3} }[/tex]

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