morag morag
  • 21-09-2020
  • Mathematics
contestada

Q bisects PR. If PR=28, and PQ = 2x+5, what is the value of x?

Respuesta :

MrRoyal
MrRoyal MrRoyal
  • 26-09-2020

Answer:

[tex]x = 4.5[/tex]

Step-by-step explanation:

Given

[tex]PR = 28[/tex]

[tex]PQ = 2x + 5[/tex]

Required

Find x

Since Q is a bisector of PR; This mean PR is divided into exactly two equal parts;

Hence:

[tex]PR = 2 * PQ[/tex]

Substitute values for PR and PQ

[tex]28 = 2 * (2x + 5)[/tex]

Divide both sides by 2

[tex]\frac{1}{2} * 28 =\frac{1}{2} * 2 * (2x + 5)[/tex]

[tex]14 = 2x + 5[/tex]

Solve for 2x

[tex]2x = 14 - 5[/tex]

[tex]2x = 9[/tex]

Solve for x

[tex]x = \frac{9}{2}[/tex]

[tex]x = 4.5[/tex]

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