upretikamala77 upretikamala77
  • 22-09-2020
  • Mathematics
contestada

how can we factorise the expression: 2x^6+17x^3+8?​

Respuesta :

Hrishii
Hrishii Hrishii
  • 22-09-2020

Answer:

[tex] (a + 2)( {a}^{2} - 2a + 4 )(2 {x}^{ 3} + 1) [/tex]

Step-by-step explanation:

[tex]2x^6+17x^3+8 \\ = 2x^6+16x^3 + {x}^{3} +8 \\ = 2{x}^{3} ( {x}^{3} + 8) + 1( {x}^{3} + 8) \\ = ( {x}^{3} + 8)(2 {x}^{ 3} + 1) \\ = ( {x}^{3} + {2}^{3} )(2 {x}^{ 3} + 1) \\ = (a + 2)( {a}^{2} - 2a + {2}^{2} )(2 {x}^{ 3} + 1) \\ = (a + 2)( {a}^{2} - 2a + 4 )(2 {x}^{ 3} + 1) \\ [/tex]

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