anae223
anae223 anae223
  • 25-09-2020
  • Mathematics
contestada

If HJ=2x+5, JK=3x-7, and KH=18 what is the value of x

Respuesta :

mhanifa
mhanifa mhanifa
  • 25-09-2020

Answer:

  • x = 4

Step-by-step explanation:

Given

  • HJ=2x+5
  • JK=3x-7
  • KH=18

We see J is between H and K, so

  • KH = HJ + JK
  • 2x + 5 + 3x - 7 = 18
  • 5x - 2 = 18
  • 5x = 20
  • x = 4

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