aaaxaxaxacagagwiwvs aaaxaxaxacagagwiwvs
  • 25-09-2020
  • Mathematics
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What is the inverse of the function f(x) = 2x + 1? 1 1 Oh(x) = 2 2 1 oh(x) = O n(x) = 5x + 199 3x-2 - 3x + 2 h(x) = x + 2​

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jimrgrant1 jimrgrant1
  • 25-09-2020

Answer:

[tex]f^{-1}[/tex](x) = [tex]\frac{x-1}{2}[/tex]

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = 2x + 1 ( subtract 1 from both sides )

y - 1 = 2x ( divide both sides by 2 )

[tex]\frac{y-1}{2}[/tex] = x

Change y back into terms of x with x = [tex]f^{-1}[/tex](x) , thus

[tex]f^{-1}[/tex](x) = [tex]\frac{x-1}{2}[/tex]

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