Answer:
[tex]\Delta T=18.24\°C[/tex]
Explanation:
Hello,
In this case, since the equation for computing the heat in terms of mass, specific heat and temperature change is:
[tex]Q=mCp\Delta T[/tex]
For the given heat and mass, and considering the specific heat of iron to be 0.444 kJ/(kg°C), the resulting temperature change is:
[tex]\Delta T=\frac{Q}{mCp}=\frac{97.2kJ}{12.0kg*0.444\frac{kJ}{kg\°C}}\\ \\\Delta T=18.24\°C[/tex]
Best regards.
