liitlemaddog52
liitlemaddog52
22-09-2016
Mathematics
contestada
x+2y+3z=6
y+2z=0
z=0
Respuesta :
nobillionaireNobley
nobillionaireNobley
22-09-2016
x + 2y + 3z = 6 . . . (1)
y + 2z = 0 . . . (2)
z = 0 . . . (3)
Putting (3) into (1) and (2) gives,
x + 2y = 6 . . . (4)
y = 0 . . . (5)
Putting (5) into (4) gives
x = 6
Therefore, x = 6, y = 0, z = 0
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