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22-10-2020
Mathematics

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[tex]c(n) = -6(-\frac{1}{3})^{n-1}[/tex]
what is the 2nd term in the sequence

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sqdancefan sqdancefan

22-10-2020

9514 1404 393

Answer:

2

Step-by-step explanation:

To find the 2nd term, put n=2 into the formula and do the arithmetic.

[tex]c(2)=-6(-\frac{1}{3})^{2-1}=-6(-\frac{1}{3}) = \dfrac{6}{3}\\\\\boxed{c(2)=2}[/tex]

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