Answer:
option 4; 0
Step-by-step explanation:
[tex]f(x) = \left \{ {{2x + 7; x<1 } \atop {10 - 5x; x \geq 1}} \right.[/tex]
Substitiute in "2" for "x".
Since "2" is greater than "1", then the second equation must be used.
Substitute in "2" of "x".
10 - 5x
10 - 5 * 2
10 - 10
0
Option 4 is 0.
