Answer:
[tex]\huge\boxed{-2i+4j}[/tex]
Step-by-step explanation:
[tex]u=-5i+2j\\\\v=-6i+4j\\\\-2u+2v=-2(-5i+2j)+2(-6i+4j)\\\\\text{use the distributive property}\\\\=(-2)(-5i)+(-2)(2j)+(2)(-6i)+(2)(4j)\\\\=10i-4j-12i+8j\\\\\text{combine like terms}\\\\=(10i-12i)+(-4j+8j)\\\\=-2i+4j[/tex]
