nicshasama
nicshasama
23-10-2016
Mathematics
contestada
How do you solve 3log_3 4a=3?
Respuesta :
Аноним
Аноним
23-10-2016
3 log₃ 4a=3
1)a(log_b c)=log_b c^a
log₃(4a)³=3
2) log_a x=n ⇔ a^n=x
log₃ (4a)³=3 ⇔ 3³=(4a)³
27=64a³
a³=27/64
a=∛(27/64)
a=3/4
Answer: a=3/4
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