Answer:
77 ft
Step-by-step explanation:
The horizontal distance is the range and it is a projectile motion.
So, range R = u²sin2θ/g where u = velocity = 50 ft/s, g = acceleration due to gravity = 32 ft/s² and θ = projection angle = 40°.
Substituting the values of the variables into the equation, we have
R = u²sin2θ/g
= (50 ft/s)²sin2(40°)/32 ft/s²
= (2500 ft²/s²)sin80°/32 ft/s²
= (2500 ft²/s²) × 0.9848/32 ft/s²
= 2462.02 ft²/s² ÷ 32 ft/s²
= 76.94 ft
≅ 77 ft to the nearest foot
