Answer:
[tex]a=3.90\ m/s^2[/tex]
Explanation:
Given that,
Initial velocity, u = 50 m/s
Final velocity, v = 75 m/s
DIstance, d = 400 m
We need to find the acceleration of the car. Let the acceleration of the car be a. We can use the third equation of motion to find it as follows :
[tex]v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(75)^2-(50)^2}{2(400)}\\\\=\dfrac{3125}{2(400)}\\\\=3.90\ m/s^2[/tex]
So, the acceleration of the car is [tex]3.90\ m/s^2[/tex].
