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  • 23-03-2021
  • Mathematics
contestada

If the perimeter was 34 and the area is 72 what is the length and width?

Respuesta :

leican4462
leican4462 leican4462
  • 23-03-2021

Answer:

xy = 72

2x + 2y = 34                 (Im assuming uts a rectangle or square)

2 (72/y) + 2y = 34

144 + 2y^2 = 34y

2y^2 - 34y + 144 = 0

y = 9 or 8

So the length is 9 and width = 8

Step-by-step explanation:

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