Respuesta :

A is the initial population
 
b is the decay coefficient
 
X is normally the time.

[tex]Y = Ae^{-bx}[/tex]

then is the population half of the initial population of A
 
for half life you will have

[tex]\frac{Y}{A} = \frac{1}{2}[/tex]

so the equation becomes

[tex]\frac{1}{2} = e^{-bX} \\ \\\ln{ \frac{1}{2}} =\ln{e^{-bX}} \\ \\ \ln{1}-\ln{2}=-bX \\bX=\ln{2}[/tex]




Otras preguntas